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–+ servings
Garlic Rosemary Lamb Chops

Garlic Rosemary Lamb Chops

Yield: 4 servings
Prep: 2 hours 20 minutes
Cook: 15 minutes
Total: 2 hours 35 minutes
Pan-seared until perfectly golden brown with an amazing garlicky, rosemary-thyme marinade. So easy yet so good!
5 stars (15 ratings)

Ingredients

  • ½ cup extra-virgin olive oil
  • 3 cloves garlic, minced
  • 1 shallot, diced
  • 1 ½ tablespoons red wine vinegar
  • 2 teaspoons Dijon mustard
  • 1 tablespoon chopped fresh rosemary
  • 1 tablespoon chopped fresh thyme leaves
  • 1 tablespoon lemon zest
  • Kosher salt and freshly ground black pepper, to taste
  • 2 ½ pounds frenched rack of lamb, excess fat trimmed and cut into chops
  • 1 tablespoon canola oil

Equipment

Instructions

  • In a medium bowl, combine olive oil, garlic, shallot, red wine vinegar, Dijon, rosemary, thyme, lemon zest, 1 teaspoon salt and 1/2 teaspoon pepper; set aside 1/4 cup of the mixture in the refrigerator until ready to serve.
  • In a gallon size Ziploc bag or large bowl, combine lamb chops and remaining olive oil mixture; marinate for at least 2 to 6 hours, turning the bag occasionally. Drain the lamb chops from the marinade.
  • Using paper towels, pat both sides of the lamb chops dry; season with salt and pepper, to taste.
  • Heat canola oil in a large cast iron skillet over medium high heat. Working in batches, add lamb chops to the skillet in a single layer and cook until it reaches an internal temperature of 145 degrees F, about 3-4 minutes per side, or until desired doneness. Let rest 5 minutes.
  • Serve immediately with reserved 1/4 cup olive oil mixture.